/**
 *  Total money transfer is the sum of all the money
 *  Net flow is the minimum transfer that is to be done
 *  This minimum transfer will be the one that has to be done
 *  which can be calculated using
 *  For each bank the minimum transfer that needs to be done
 *  will be the extra money that it has
 *  i.e. outflow for each bank - inflow for each bank
 *  This amount will be the one that is spare with the bank and
 *  will be transfering it to other bank
 *  so 
 *  Summation of (outflow-inflow) is the answer
 */


#include <stdio.h>
#include <stdlib.h>

#define DEBUG 1

int readline ( char * str ) {

    int i = 0;
    char ch;
    while ( (ch=getchar()) != '\n' ) {
        str[i++] = ch;
    }
    str[i] = '\0';
    return i;
}

int main ( int argc , char * argv[] ) {

    int t , count = 0;
    scanf("%d" , &t);

    int array[1000][1000];

    while ( t != 0 ) {

        count ++;
        int total_flow = 0;
        int net_flow = 0;

        int i , j;
        for ( i = 0 ; i < t ; i++ ) {
            for ( j = 0 ; j < t ; j++ ) {
                scanf("%d" , &array[i][j] );
                total_flow += (array[i][j]);
            }
        }

        for ( i = 0 ; i < t ; i++ ) {
            int out_flow = 0;
            int in_flow = 0;

            for ( j = 0 ; j < t ; j++ ) {
                out_flow += (array[i][j]);
                in_flow += (array[j][i]);
            }

            if ( out_flow >= in_flow ) {
                net_flow += (out_flow - in_flow);
            }
        }

        printf("%d. %d %d\n" , count , total_flow , net_flow );

        scanf("%d" , &t);

    }

    return 0;
}