SPOJ DIGNUM Solution

| July 01, 2015

The correct, optimal and working solution for programming question DIGNUM on spoj

/*
 * DIGNUM.cpp
 *
 *  Created on: Jun 9, 2014
 *      Author: Arpit Bhayani
 */

#include <cstdio>
#include <cstdlib>
#include <iostream>

using namespace std;

#define DEBUG 0
#define gc getchar
#define ll long long

void scanint(ll int &x) {
	register ll int c = gc();
	x = 0;
	for (; (c < 48 || c > 57); c = gc())
		;
	for (; c > 47 && c < 58; c = gc()) {
		x = (x << 1) + (x << 3) + c - 48;
	}
}

int readline(char * str) {

	int i = 0;
	char ch;
	while ((ch = getchar()) != '\n') {
		str[i++] = ch;
	}
	str[i] = '\0';
	return i;
}

int main(int argc, char * argv[]) {

	string numbers[3];

	while (!cin.eof()) {
		getline(cin, numbers[0]);
		if (!cin)
			break;
		getline(cin, numbers[1]);
		getline(cin, numbers[2]);

		for (int i = 0; i < (numbers[0].size() / 3); i++) {

			if (numbers[0][1 + i * 3] == ' ') {     // {1, 4}
				if (numbers[1][1 + i * 3] == '_') {
					cout << "4";
				} else {
					cout << "1";
				}
			} else { // {0, 2, 3, 5, 6, 7, 8, 9}
				if (numbers[1][0 + i * 3] == '|') { // {0, 5, 6, 8, 9}
					if (numbers[1][1 + i * 3] == '_') { // {5, 6, 8, 9}
						if (numbers[1][2 + i * 3] == '|') { // {8, 9}
							if (numbers[2][0 + i * 3] == '|') { // {8}
								cout << "8";
							} else { // {9}
								cout << "9";
							}
						} else { // {5, 6}
							if (numbers[2][0 + i * 3] == '|') { // {6}
								cout << "6";
							} else { // {5}
								cout << "5";
							}
						}
					} else { // {0}
						cout << "0";
					}
				} else { // {2, 3, 7}
					if (numbers[1][1 + i * 3] == '_') { // {2, 3}
						if (numbers[2][0 + i * 3] == '|') { // {2}
							cout << "2";
						} else { // {3}
							cout << "3";
						}
					} else { // {7}
						cout << "7";
					}
				}
			}

		}

		cout << endl;
	}

	return 0;
}